I through R3 was found to be -0.1857 A
Assignment 2
After the circuit was redesigned to give output = 2*(1-e^(-t/tau))
Adding 2 sinusoids 3sin(2t+10 degree) and 5cos(2t-30 degree)
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Adding the same 2 sinusoids with f = 10 Hz
Assignment 3
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Assignment 4
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Monday, March 10, 2014
MATLAB - INTRODUCTION TO NUMERICAL COMPUTATION
Assignment 1
I through R3 was found to be -0.1857 A
Assignment 2
The circuit with tau = 100 ms (blue plot) has the lowest output sooner.
After the circuit was redesigned to give output = 2*(1-e^(-t/tau))
Adding 2 sinusoids 3sin(2t+10 degree) and 5cos(2t-30 degree)
Script for adding 2 sinusoids
Adding the same 2 sinusoids with f = 10 Hz
Assignment 3
Assignment 4
I through R3 was found to be -0.1857 A
Assignment 2
After the circuit was redesigned to give output = 2*(1-e^(-t/tau))
Adding 2 sinusoids 3sin(2t+10 degree) and 5cos(2t-30 degree)
Adding the same 2 sinusoids with f = 10 Hz
Assignment 3
Assignment 4
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